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**Question:-**Recently Oz has found a magical string consisting of the single digit "1". After experimenting on the string, Oz found a weird magical property of the string that is whenever he touches the string then each digit "1" of string changed to the digit "0" and

each digit "0" of string changed to "01". Oz found this property interesting and immediately asked a question to RK :

"How many 1's and 0's will be in the magical string if he touches the string M times ?"

**Input :**

The first line contains the number of test cases T. Each test case consists of a positive integer - M.

**Output :**

For each test case output two space-separated integers, number of 1's and number of 0's in the magical string if Oz

touches the string M times.

**Constraints :**

1<= T <=20

1<= M <=90

**Sample Input (Plaintext Link)**

2

1

2

**Sample Output (Plaintext Link)**

0 1

1 1

**Check-**Geeksforgeeks solution for School, Basic, Easy, Medium, Hard Domain.

Copy the full solution or colored code and paste into the hacker earth editor and click to Run Code if the code runs successfully then click to Submit Code.

**Solution:-**

#include<iostream>

using namespace std;

int main()

{

//Ghanendra

int t=0,m=1,n,i,j,t1;

int a1=1,a2=1;

cout<<"Enter the no of times Sample Input\n\n";

cin>>n;

cout<<t<<" "<<m<<endl;

for(i=0;i<n;i++)

{

cout<<a1<<" "<<a2<<endl;

t1=a1;

a1=a2;

a2=a2+t1;

}

}

**Output:-**

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