# Accessing Inherited Functions Hackerrank Solution in C++

You are given three classes A, B and C. All three classes implement their own version of func. In class A, func multiplies the value passed as a parameter by 2: Accessing Inherited Functions Hackerrank Solution in C++.

class A
{
public:
A(){
callA = 0;
}
private:
int callA;
void inc(){
callA++;
}

protected:
void func(int & a)
{
a = a * 2;
inc();
}
public:
int getA(){
return callA;
}
};

In class B, func multiplies the value passed as a parameter by 3:

class B
{
public:
B(){
callB = 0;
}
private:
int callB;
void inc(){
callB++;
}
protected:
void func(int & a)
{
a = a * 3;
inc();
}
public:
int getB(){
return callB;
}
};

In class C, func multiplies the value passed as a parameter by 5:

class C
{
public:
C(){
callC = 0;
}
private:
int callC;
void inc(){
callC++;
}
protected:
void func(int & a)
{
a = a * 5;
inc();
}
public:
int getC(){
return callC;
}
};

You are given a class D:

class D
{

int val;
public:
//Initially val is 1
D()
{
val = 1;
}

//Implement this function
void update_val(int new_val)
{

}
//For Checking Purpose
void check(int); //Do not delete this line.
};

You need to modify the class D and implement the function update_val which sets D's val to new_val by manipulating the value by only calling the func defined in classes A, B and C.

It is guaranteed that new_val has only 2, 3 and 5 as its prime factors.

Input Format

Implement class D's function update_val. This function should update D's val only by calling A, B and C's func.

Constraints

1 <= new_val <= 10000
Note: The new_val only has 2, 3 and 5 as its prime factors.

Sample Input

new_val = 30

Sample Output

A's func will be called once.
B's func will be called once.
C's func will be called once.

Explanation

Initially, val = 1.

A's func is called once:

val = val*2
val = 2

B's func is called once:

val = val*3
val = 6

C's func is called once:

val = val*5
val = 30

## Accessing Inherited Functions Hackerrank Solution in C++

``````#include <iostream>
using namespace std;

int callA = 0;
int callB = 0;
int callC = 0;
class A
{
protected:

void func(int & a)
{
a = a * 2;
callA++;
}
};

class B
{
protected:
void func(int & a)
{
a = a * 3;
callB++;
}
};

class C
{
protected:
void func(int & a)
{
a = a * 5;
callC++;
}
};

class D: public A, public B, public C
{
int val;
public:
//Initially val is 1
D()
{
val = 1;
}

//Implement this function
void update_val(int new_val)
{
int a = new_val;
while (a % 2 == 0)
{
a = a / 2;
A::func(val);
}

while (a % 3 == 0)
{
a = a / 3;
B::func(val);
}

while (a % 5 == 0)
{
a = a / 5;
C::func(val);
}
}

//For Checking Purpose
void check(int);	//Do not delete this line.
};

void D::check(int new_val)
{
update_val(new_val);
cout << "Value = " << val << endl << "A's func called " << callA << " times " << endl << "B's func called " << callB << " times " << endl << "C's func called " << callC << " times" << endl;
}

int main()
{
D d;
int new_val;
cin >> new_val;
d.check(new_val);

}``````

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#### post written by: Ghanendra Yadav

Hi, I’m Ghanendra Yadav, SEO Expert, Professional Blogger, Programmer, and UI Developer. Get a Solution of More Than 500+ Programming Problems, and Practice All Programs in C, C++, and Java Languages. Get a Competitive Website Solution also Ie. Hackerrank Solutions and Geeksforgeeks Solutions. If You Are Interested to Learn a C Programming Language and You Don't Have Experience in Any Programming, You Should Start with a C Programming Language, Read: List of Format Specifiers in C.