C++ Program To Find Sum Of The Given Series x+x^2/2+x^3/3+x^4/4+ . . . . x^n/n

Problem :- Write A C++ Program To Find Sum Of The Given Series  x+x^2/2+x^3/3+x^4/4+ . . . . x^n/n

Logic :- This is very simple series just take a input a value of 'X' and numbers of terms and calculate the sum .at the end print the sum the logic is given below .

for(i=1;i<=n;++i)

{

sum+=pow(x,i)/i;

}

Try Yourself C++ Program To Find Sum Of Given Series 1^2+3^2+5^2+ . . . . n^2

Solution :-

#include<iostream>

#include<math.h>

using namespace std;

int main()

{

//By-Ghanendra Yadav

int i,n;

float x,sum=0;

cout<<"\nx+x^2/2+x^3/3+…..+x^n/n\n";

cout<<"\nEnter value of x and n :\n";

cin>>x>>n;

for(i=1;i<=n;++i)

{

sum+=pow(x,i)/i;

}

cout<<"\nSum Is = "<<sum<<endl;

return 0;

}

Output:-