C++ Program To Find Sum Of The Given Series 1/2+4/5+7/8+ . . . N

Problem :- Write A C++ Program To Find Sum Of The Given Series 1/2+4/5+7/8+.......N

Logic :- As we can see the the dividend of the given series is increase by 3 each time and divisor is also increasing by 3 but divisor = dividend+1 so according to the series we can use for loop 

Logic is Given Below .

for(i=0;i<n;++i)

{

x=a/(a+1);

sum+=x;

a+=3;

}

Try Yourself C++ Program To Find Sum Of The Given Series 1+2+3+4+5+6 . . . . n

Solution :-

#include<iostream>

using namespace std;

int main()

{

//By-Ghanendra Yadav

int i,n;

float sum=0,x,a=1;

cout<<"\n1/2+4/5+7/8+……'\n";

cout<<"\nEnter The Number of Terms \n";

cin>>n;

for(i=0;i<n;++i)

{

x=a/(a+1);

sum+=x;

a+=3;

}

cout<<"\n Sum = "<<sum<<endl;

return 0;

}

Output:-