C++ Program To Find Sum Of The Following Series 1+2+3+4+5+6 . . . . . n

Problem :- Write A C++ Program To Find Sum Of The Following Series 1+2+3+4+5+6 . . . . . n .

Logic :- This is very simple series you just need to print sum of 1 to n terms ,there are two method you can use either use for loop or use formula Running time of using formula is Constant or Running time of using for loop is O(n) in words ' Order of N '

Method 1:- sum of series from 1 to N.

Formula =n(n+1)/2

Method 2:- sum of series from 1 to N.

for(i=1;i<=n;++i)

{

sum+=i;

}

If you are interested then you can modified this series for large number or you can try below series .

Try Yourself C++ Program To Find Sum Of The Given Series 1/2+4/5+7/8+ . . . N

Solution :-

Method 1:- Using For Loop

#include<iostream>

using namespace std;

int main()

{

//By-Ghanendra Yadav

int i,n,sum=0;

cout<<"\n1+2+3+4+5+6+……+n\n";

cout<<"\nEnter The Value Of N:\n";

cin>>n;

for(i=1;i<=n;++i)

{

sum+=i;

}

cout<<"\nSum = "<<sum<<endl;

return 0;

}

Method 2:- Using Formula

#include<iostream>

using namespace std;

int main()

{

//By-Ghanendra Yadav

int i,n,sum=0;

cout<<"\n1+2+3+4+5+6+……+n\n";

cout<<"\nEnter The Value Of N:\n";

cin>>n;

sum=(n*(n+1))/2;

cout<<"\nSum = "<<sum<<endl;

return 0;

}

Output:-

Method 1:-

Method 2:-