11/16/2015

C++ Program To Find Sum Of Given Series 1^2+3^2+5^2+ . . . . n^2

Problem :- Write A C++ Program To Find Sum Of Series 1^2+3^2+5^2+ . . . . n^2

Logic :- In This series loop initialize with zero and increase by 2 cause we have to find the sum of the power of 2 odd  number so first print odd number then power of 2 after that sum .
 i+=2 ( increase by 2 )
i*i ( Power of 2 )
sum+=(i*i); ( sum of odd )

Try Yourself C++ Program To Find Sum Of Series 1+x^1+x^2+x^3+ . . . . . x^n

Solution :-

#include<iostream>
using namespace std;
int main()
{
//By-Ghannedra Yadav
int n,i;
long sum=0;

cout<<"1^2+3^2+5^2+……+n^2\n\nEnter Value of N :\n";
cin>>n;

for(i=1;i<=n;i+=2)
{
sum+=(i*i);
}

cout<<"\nSum of given series is = "<<sum<<endl;
return 0;
}

Output:-

C++ Program To Find Sum Of Given Series 1^2+3^2+5^2+ . . . . n^2

Ghanendra Yadav

Ghanendra Yadav

Hello, I Am Ghanendra Yadav Owner of This Blog, I am professional Blogger and Programmer. I Love Programming, Logo Making, And Banner Designing. My Highest Qualification is MCA From NIT Warangal. You Can Find Me On Social Media Through Below Link And If You Have Any Query Related To Programming And Other Subject Comment Below or You Can Mail Me I Will Try To Answer Within 24 Hours Email:- yghanendra@student.nitw.ac.in

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