**Problem:-**You are given an array of N+2 integer elements. All elements of the array are in range 1 to N. And all elements occur once except two numbers which occur twice. Find the two repeating numbers.

**Input:**

The first line of the input contains an integer T, denoting the total number of test cases. Then T test cases follow Each test case consists of two lines. The first line of each test case contains an integer N denoting the range of numbers to be inserted in an array of size N+2. The second line of each test case contains the N+2 space separated integers denoting the array elements.

**Output:**

Print the two elements occurring twice in the array. Order of the two elements must be preserved as in the original list, i.e., print the element which arrives first(2nd time).

**Constraints:**

1 ≤ T ≤ 30

1 ≤ N ≤ 100

**Example:**

**INPUT**

1

4

1 2 1 3 4 3

1

4

1 2 1 3 4 3

**OUTPUT**

**1 3**

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**Solution:-**

#include<iostream>

using namespace std;

int main()

{

int t;

cin>>t;

while(t--)

{

int n;

cin>>n;

int a[n+2],b[n+2]={};

for(int i=0;i<n+2;i++)

{

cin>>a[i];

b[a[i]]=b[a[i]]+1;

if(b[a[i]]==2)

cout<<a[i]<<" ";

}

cout<<endl;

}

return 0;

}

**Output:-**

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