06/04/2017

Geeksforgeeks Solution For " Sum of divisors "

GeeksforGeeks Solution For Hard Domain .Below You Can Find The Solution Of  School Basic ,Easy ,Medium . Or Hackerrank Solution You Can Also Direct Submit Your Solution to Geeksforgeeks Same Problem .You Need to login then you can submit you answers 

Problem :- Given a natural number, calculate sum of all its proper divisors. A proper divisor of a natural number is the divisor that is strictly less than the number.

For example, number 20 has 5 proper divisors: 1, 2, 4, 5, 10, and the divisor summation is: 1 + 2 + 4 + 5 + 10 = 22.

Submit Your Solution :- Click Here 

Solution :- 

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        int n,i,res=0;
        cin>>n;
        for(i=1;i<=n/2;i++)
        {
            if(n%i==0)
            {
                res+=i;
            }
        }
        cout<<res<<endl;
    }
    return 0;
}

Output:-



Geeksforgeeks Solution For " Sum of divisors "

Previous Post
Next Post

post written by:

Hi, I’m Ghanendra Yadav, SEO Expert, Professional Blogger, Programmer, and UI Developer. Get a Solution of More Than 500+ Programming Problems, and Practice All Programs in C, C++, and Java Languages. Get a Competitive Website Solution also Ie. Hackerrank Solutions and Geeksforgeeks Solutions. If You Are Interested to Learn a C Programming Language and You Don't Have Experience in Any Programming, You Should Start with a C Programming Language, Read: List of Format Specifiers in C.
Follow Me

0 Comments: