# Geeksforgeeks Solution For " Different ways to Spell a Number "

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Problem :- Given a  number. The number may contain many same continuous digits in it. The task is to count number of ways to spell the number.
For example, consider 8884441100, one can spell it simply as triple eight triple four double two and double zero. One can also spell as double eight, eight, four, double four, two, two, double zero.

Solution :-

#include<bits/stdc++.h>
using namespace std;
typedef long long int ll;

ll spellsCount(string num)
{
int n = num.length();
ll result = 1;
for (int i=0; i<n; i++)
{
int count = 1;
while (i < n-1 && num[i+1] == num[i])
{
count++;
i++;
}
result = result * pow(2, count-1);
}
return result;
}

int main()
{
int t;
cin>>t;
while(t--)
{
string num ;
cin>>num;
cout << spellsCount(num);
cout<<endl;
}
return 0;
}

Output:-

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#### post written by: Ghanendra Yadav

Hi, I’m Ghanendra Yadav, SEO Expert, Professional Blogger, Programmer, and UI Developer. Get a Solution of More Than 500+ Programming Problems, and Practice All Programs in C, C++, and Java Languages. Get a Competitive Website Solution also Ie. Hackerrank Solutions and Geeksforgeeks Solutions. If You Are Interested to Learn a C Programming Language and You Don't Have Experience in Any Programming, You Should Start with a C Programming Language, Read: List of Format Specifiers in C.