3/05/2017

Geeksforgeeks Solution For " Sum of all prime numbers between 1 and N. "

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Problem :- Given a positive integer N, calculate the sum of all prime numbers between 1 and N.

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Solution :-

#include <iostream>
#include<math.h>
using namespace std;

int main() 
{
    int A[1000000];
int k=0,i,j,flag,s,t,num;
long sum;
for(i=2;i<1000000;i++)
{
   if(i>2&&i%2==0)
     continue;
   s=sqrt(i);
   flag=0;
   for(j=2;j<=s;j++)
   {
       if(i==j)
          continue;
       if(i%j==0)
       {
           flag=1;
           break;
       }         
   }
   if(flag==0)
   {
       A[k]=i;
       k++;
   }      
}
cin>>t;
while(t--)
{   sum=0;
   cin>>num;
   i=0;
   while(A[i]<=num)
   {
       sum=sum+A[i];
         i++;
   }  
   cout<<sum<<"\n";
      
}
return 0;
}

Output:-
Geeksforgeeks Solution For " Sum of all prime numbers between 1 and N. "


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