# Geeksforgeeks Solution For " Sum of all prime numbers between 1 and N. "

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Problem :- Given a positive integer N, calculate the sum of all prime numbers between 1 and N.

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Solution :-

#include <iostream>
#include<math.h>
using namespace std;

int main()
{
int A[1000000];
int k=0,i,j,flag,s,t,num;
long sum;
for(i=2;i<1000000;i++)
{
if(i>2&&i%2==0)
continue;
s=sqrt(i);
flag=0;
for(j=2;j<=s;j++)
{
if(i==j)
continue;
if(i%j==0)
{
flag=1;
break;
}
}
if(flag==0)
{
A[k]=i;
k++;
}
}
cin>>t;
while(t--)
{   sum=0;
cin>>num;
i=0;
while(A[i]<=num)
{
sum=sum+A[i];
i++;
}
cout<<sum<<"\n";

}
return 0;
}

Output:-

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#### post written by: Ghanendra Yadav

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