# Geeksforgeeks Solution For " Smaller and Larger "

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Problem :- Given a sorted array and a value x, find the number of array elements less than or equal to x and elements more than or equal to x.

Solution :-

#include <iostream>
#include <vector>
using namespace std;
int main()
{
int t1;
cin>>t1;
while(t1--)
{
int n,x,i,count=0,temp=0;
cin>>n>>x;
vector <int> arr(n);

for(i=0;i<n;i++)
cin>>arr[i];

for(i=0;i<n;i++)
{
if(arr[i]<=x)
temp++;
else if(arr[i]>=x)
count++;
}
cout<<temp<<" "<<count<<endl;
}

return 0;
}

Output:-

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#### post written by: Ghanendra Yadav

Hi, I’m Ghanendra Yadav, SEO Expert, Professional Blogger, Programmer, and UI Developer. Get a Solution of More Than 500+ Programming Problems, and Practice All Programs in C, C++, and Java Languages. Get a Competitive Website Solution also Ie. Hackerrank Solutions and Geeksforgeeks Solutions. If You Are Interested to Learn a C Programming Language and You Don't Have Experience in Any Programming, You Should Start with a C Programming Language, Read: List of Format Specifiers in C.