# Geeksforgeeks Solution For " nPr "

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Problem :- Write a program to calculate nPr. nPr represents n permutation r and value of nPr is (n!) / (n-r)!.

Solution :-

#include <iostream>
using namespace std;
long long int fact(int x);
int main()
{
int t;
cin>>t;
while(t--)
{
int n,r,npr;
long long int p=1;
cin>>n>>r;
npr=n-r+1;
for(int i=npr;i<=n;i++)
{
p=p*i;
}
cout<<p<<endl;
}
return 0;
}

Output:-

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