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**Problem :-**Write a program to find the compund interest for given principal amount P , time T(in years), compounds N times in a year at rate R. Calculate floor of future value of given principal amount.

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**Solution :-**

#include <iostream>

#include <math.h>

using namespace std;

int main()

{

int t1;

cin>>t1;

while(t1--)

{

double p=0,n=0,t=0,r=0,i=0,co=0,po=0;

cin>>p>>t>>n>>r;

i=(1+r/(n*100));

co=pow(i,n*t);

po=p*co;

cout<<floor(po)<<endl;

}

return 0;

}

**Output:-**

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