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**Problem :-**Given a natural number n, print all distinct divisors of it including 1 and the number itself.

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**Solution :-**

#include <iostream>

using namespace std;

int main()

{

int t;

cin>>t;

while(t--)

{

int n,i,flag=0;

cin>>n;

for(i=1;i<=n;i++)

{

if(n%i==0)

cout<<i<<" ";

}cout<<endl;

}

return 0;

}

**Output:-**

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