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**Problem :-**Given two force vectors, find out whether they are parallel, perpendicular or neither. Let the first vector be A = a1 i +a2 j + a3 k and the second vector be B = b1 i + b2 j + b3 k.

A.B = a1*b1 + a2*b2 + a3*b3

A x B = (a2*b3 - a3*b2) i - (a1*b3 - b1*a3) j + (a1*b2 - a2*b1) k

|A|^2 = a1^2 + a2^2 + a3^2

If A.B = 0, then A and B are perpendicular.

If |A X B|^2 = 0, then A and B are parallel.

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**Solution :-**

**#include <iostream>**

using namespace std;

int main()

{

int t;

cin>>t;

while(t--)

{

int a1=0,a2=0,a3=0,b1=0,b2=0,b3=0,par,per;

cin>>a1>>a2>>a3>>b1>>b2>>b3;

par=(a2*b3-a3*b2)-(a1*b3-b1*a3)+(a1*b2-a2*b1);

per= a1*b1 + a2*b2 + a3*b3;

if(par==0)

cout<<"1\n";

else if(per==0)

cout<<"2\n";

else

cout<<"0\n";

}

return 0;

}

**Output:-**

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