# Geeksforgeeks Solution For " Maximum Possible Sum of Products "

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Problem :- You will be given two arrays A and B of positive integers. The number of values in both the arrays will be the same say N. Your task is to find the maximum sum of products of their elements. Each element in A has to be multiplied with exactly one element in B and vice versa such that each element of both the arrays appears exactly once and the sum of product produced is maximum.

if A = {5,1,3,4,2} and B = {8,10,9,7,6} then a possible sum of product is 5*6 + 1*7 + 3*9 + 4*10 + 2*8.

Solution :-

#include <iostream>
#include<algorithm>
#include <vector>
using namespace std;
int main()
{
int t,i,j;
cin>>t;
while(t--)
{
int n,sum=0;
cin>>n;
vector <int> arr(n);
vector <int> arr1(n);
for(i=0;i<n;i++)
{
cin>>arr[i];
}

for(j=0;j<n;j++)
{
cin>>arr1[j];
}
sort(arr.begin(),arr.end());
sort(arr1.begin(),arr1.end());
for(i=n-1;i>=0;i--)
{
sum=sum+arr[i]*arr1[i];
}
cout<<sum<<endl;
}

return 0;
}

Output:-

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#### post written by: Ghanendra Yadav

Hi, I’m Ghanendra Yadav, SEO Expert, Professional Blogger, Programmer, and UI Developer. Get a Solution of More Than 500+ Programming Problems, and Practice All Programs in C, C++, and Java Languages. Get a Competitive Website Solution also Ie. Hackerrank Solutions and Geeksforgeeks Solutions. If You Are Interested to Learn a C Programming Language and You Don't Have Experience in Any Programming, You Should Start with a C Programming Language, Read: List of Format Specifiers in C.