# Geeksforgeeks Solution For " Common Divisors "

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Problem :- Given two integer numbers, the task is to find count of all common divisors of given numbers?
Input : a = 12, b = 24
Output: 6
// all common divisors are 1, 2, 3,
// 4, 6 and 12

Input : a = 3, b = 17
Output: 1
// all common divisors are 1

Input : a = 20, b = 36
Output: 3
// all common divisors are 1, 2, 4

Solution :-

#include <bits/stdc++.h>
using namespace std;
int main()
{
int t;
cin>>t;
while(t--)
{
int n,i,k,j,res=0;
cin>>n>>k;
for(i=1,j=1;i<=n/2||i<=k/2;i++,j++)
{
if(n%i==0 && k%j==0)
res++;
}

cout<<res<<endl;
}
return 0;
}

Output :-

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#### post written by: Ghanendra Yadav

Hi, I’m Ghanendra Yadav, SEO Expert, Professional Blogger, Programmer, and UI Developer. Get a Solution of More Than 500+ Programming Problems, and Practice All Programs in C, C++, and Java Languages. Get a Competitive Website Solution also Ie. Hackerrank Solutions and Geeksforgeeks Solutions. If You Are Interested to Learn a C Programming Language and You Don't Have Experience in Any Programming, You Should Start with a C Programming Language, Read: List of Format Specifiers in C.