C Program For Denomination of an Amount Using While Loop

Problem :- Write A C Program To Find Denomination Needed for A Given Amount Along With The Total Number of Notes .

Generally Notes are used in banks are given below in descending Order .Ii is dependent to country wise their are some country Denomination

INDIA ( Rupees )            USA ( Dollar )             INDIA ( Rupees )
( Before 8 Nov. 2016 )     ( Present )                        ( Present )

1000                                 100                                     2000
500                                    50                                        500
100                                    20                                        100
50                                      10                                          50
20                                        5                                          20
10                                        2                                          10
5                                          1                                            5
2                                                                                        2
1                                                                                        1

Logic :- The Logic Behind we have to divide a money by Above Money lets take a example Suppose money is 16108 then follow the Step We are taking a example of Indian Currency In present

Step 1:- Then First we divide 16108  by 2000 then we get 8    ,2000 rs notes then go to step 2

Step 2:-  After divide 2000 we get a remainder 108 The we know that 108 is not divisible by 500 so go to next step

Step 3:- Now divide 108 by 100 then we get ,100 rs note now remainder is 8 go to next step

Step 4:- 8 is divisible by 50 and 20 nor 10 so we escape now go to next step

Step 5:- Now divide 8 by 5 we get a 1 ,5 rs notes and remainder is 3 so go to next step

Step 6:- Now divide 3 by 2 we get 1 ,2 rs notes and remainder is 1

Step 7:- This is a Last step divide 1 by 1 we get zero remainder now print the total no of denomination needed and along with total no of count require to fulfill a requirement

So for 16108 You Need to

No.

8 * 2000 = 16000
1 * 100 = 100
1 * 5 = 5
1 * 2 = 2
1 * 1 = 1

Total =12 Notes For minimum Transaction

Solution :-

Method 1 :- Denomination For Indian Rupees

#include<stdio.h>
int main()

Visit http://www.programmingwithbasics.com/
*/
int amt, r2000=0, r500=0, r100=0, r50=0, r20=0, r10=0, r5=0, r2=0 , r1=0 ,count=0;

printf("Enter The Amount in Rupees : \n\n") ;
scanf("%d", &amt) ;

while(amt >= 2000)

r2000 = amt / 2000 ;
amt = amt % 2000;
printf("\nTotal Number Of 2000 Rupees Notes : %d", r2000) ;
break ;
}
while(amt >= 500)

r500 = amt / 500 ;
amt = amt % 500;
printf("\nTotal Number Of 500 Rupees Notes : %d", r500) ;
break ;

while(amt >= 100)

r100 = amt / 100 ;
amt = amt % 100;
printf("\nTotal Number Of 100 Rupees Notes : %d", r100) ;
break ;

while(amt >= 50)

r50 = amt / 50 ;
amt = amt % 50;
printf("\nTotal Number Of 50 Rupees Notes : %d", r50) ;
break ;
}
while(amt >= 20)

r20 = amt / 20 ;
amt = amt % 20;
printf("\nTotal Number Of 20 Rupees Notes : %d", r20) ;
break ;
}
while(amt >= 10)

r10 = amt / 10 ;
amt = amt % 10;
printf("\nTotal Number Of 10 Rupees Notes Or Coin : %d", r10) ;
break ;

while(amt >= 5)

r5 = amt / 5 ;
amt = amt % 5;
printf("\nTotal Number Of 5 Rupees Notes Or Coin : %d", r5) ;
break ;

while(amt >= 2)

r2 = amt / 2 ;
amt = amt % 2;
printf("\nTotal Number Of 2 Rupees Notes Or Coin : %d", r2) ;
break ;

while(amt >= 1)

r1 = amt / 1 ;
amt = amt % 1;
printf("\nTotal Number Of 1 Rupees Note Or Coin : %d", r1) ;
break ;
}
count = r2000 + r500 + r100 + r50 + r20 + r10 + r5 + r2 + r1;
printf("\n\nTotal Number Of Notes Require : %d\n", count) ;
return 0;
}

Method 2 :- Denomination For USA Dollar

#include<stdio.h>
int main()

Visit http://www.programmingwithbasics.com/
*/
int amt, r100=0, r50=0, r20=0, r10=0, r5=0, r2=0 , r1=0 ,count=0;

printf("Enter The Amount in Dollar : \n\n") ;
scanf("%d", &amt) ;

while(amt >= 100)

r100 = amt / 100 ;
amt = amt % 100;
printf("\nTotal Number Of 100 Dollar : %d", r100) ;
break ;

while(amt >= 50)

r50 = amt / 50 ;
amt = amt % 50;
printf("\nTotal Number Of 50 Dollar : %d", r50) ;
break ;
}
while(amt >= 20)

r20 = amt / 20 ;
amt = amt % 20;
printf("\nTotal Number Of 20 Dollar : %d", r20) ;
break ;
}
while(amt >= 10)

r10 = amt / 10 ;
amt = amt % 10;
printf("\nTotal Number Of 10 Dollar Or Coin : %d", r10) ;
break ;

while(amt >= 5)

r5 = amt / 5 ;
amt = amt % 5;
printf("\nTotal Number Of 5 Dollar Or Coin : %d", r5) ;
break ;

while(amt >= 2)

r2 = amt / 2 ;
amt = amt % 2;
printf("\nTotal Number Of 2 Dollar Or Coin : %d", r2) ;
break ;

while(amt >= 1)

r1 = amt / 1 ;
amt = amt % 1;
printf("\nTotal Number Of 1 Dollar Or Coin : %d", r1) ;
break ;
}
count = r100 + r50 + r20 + r10 + r5 + r2 + r1;
printf("\n\nTotal Number Of Dollar Require : %d\n", count) ;
return 0;
}

Output:-

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