Problem :- C Program To Find Row In An Array That Include The Greatest Amount Of Even Number

Input Is Below

#include<iostream>

using namespace std;

int main()

{

int a[10][10],n,l,i,j,count=0;

cout<<"\nEnter The Matrix Size (l*l)\n";

cin>>l;

cout<<"\nEnter The Row Number Of Matrix\n";

cin>>n;

if(n<0||n<=l)

{

}

else

{

cout<<"\nRow Is Exceed The Limit Enter Value >0 And Less Than Size Of Matrix \n";

exit(0);

}

cout<<"Enter The Matrix Value\n";

for(i=1;i<=l;i++)

for(j=1;j<=l;j++)

cin>>a[i][j];

cout<<"\n\nMatrix Row Is Given Below\n\n";

for(i=1;i<=l;i++)

{

cout<<a[n][i]<<" ";

if(a[n][i]%2==0)

count++;

}

cout<<"\n\nNo. Of Even Number In Row IS = "<<count;

return 0;

}

Input Is Below

**Solution :-**

using namespace std;

int main()

{

int a[10][10],n,l,i,j,count=0;

cout<<"\nEnter The Matrix Size (l*l)\n";

cin>>l;

cout<<"\nEnter The Row Number Of Matrix\n";

cin>>n;

if(n<0||n<=l)

{

}

else

{

cout<<"\nRow Is Exceed The Limit Enter Value >0 And Less Than Size Of Matrix \n";

exit(0);

}

cout<<"Enter The Matrix Value\n";

for(i=1;i<=l;i++)

for(j=1;j<=l;j++)

cin>>a[i][j];

cout<<"\n\nMatrix Row Is Given Below\n\n";

for(i=1;i<=l;i++)

{

cout<<a[n][i]<<" ";

if(a[n][i]%2==0)

count++;

}

cout<<"\n\nNo. Of Even Number In Row IS = "<<count;

return 0;

}

**Output:-**
number

ReplyDeleteamount - of uncountable

number - of countable

amount of sand/salt/flour

number of characters/flowers/numbers