**Problem :-**Write A C Program To Check Number Is Divisible By 11 Or Not Using (VEDIC MATH)

**Logic :-**Here Is A Clarification Of Below Program If We Want To Check Any No Is Divisible By 11 Or Not Its Very Simple You Have To Calculate Even And Odd Place Sum If Both Are Shame The No Also Will Be Divisible By 11 If Not Equal Then NOT Divisible By Now Check Code

**Example :-**

So take a Example 161051

So Add Even place and odd Place Numbers

**Even :-**6+0+1=7

**Odd :-**1+1+5=7

Now Compare Even Or Odd Number addition If Both Are Equal then Number is Divisible Else Not .

If you got a Solution then Try Below Problems .

Try Yourself C Program For Denomination of an Amount Using While Loop

Try Yourself C Program For Denomination of an Amount Using While Loop

**Solution :**

#include<stdio.h>

#include<conio.h>

void main()

{

//Ghanendra yadav

long int r=0,i=1,odd=0,even=0,no,n,rev=0;

while(1)

{

printf("\n\nEnter Any Number : ");

scanf("%ld",&n);

no=n;

while(no!=0)

{

r=no%10;

rev=rev*10+r;

no=no/10;

}

while(rev!=0)

{

r=rev%10;

if(i%2==0)

{

even=even+r;

}

else

{

odd=odd+r;

}

rev=rev/10;

i++;

}

printf("\nOdd Digit sum = %ld \n ",odd);

printf("\nEven Digit Sum = %ld \n ",even);

if(odd==even)

printf("\n%ld Is Divisible by 11\n\n",n);

else

printf("\n%ld Is Not Divisible by 11\n\n",n);

}

getch();

}

**Output:-**

reverse is not require.....

ReplyDeleteWhy you reverse the number it is totally Unnecessary !!

ReplyDelete#include // line 1 //no need to reverse the no

ReplyDeletevoid main()

{

int no,n=0,rem=0,n1=0;

printf("ENTER THE NO TO CHECK DIV BY 11\n"); //line 5

scanf("%d",&no);

while(no!=0)

{

rem=no%10; //taking no rem for shorting and add or sub in line 14 & 19

no=no/10; //line 10

n++;

if(n%2==0) //this function will help shorting even and odd places

{

n1=n1+rem;

printf("eve=%d %d\t",rem,n1); //line 15 //printing output to check and understand the outcome

}

else

{

n1=n1-rem; //if you do n1=rem-n1 that is {let rem=7 and 'int n1=0'} so 7-0=7 but we need 0-7=-7

printf("odd=%d %d\t",rem,n1); //line 20 //printing output to check and understand the outcome

}

}

if(n1==0)

{ printf("\n the no is div by 11\n");}

else //line 25

{ printf("\n the no is div not by 11\n");}

}