21/10/2015

C++ Program For Denomination of an Amount Using While Loop

Problem :- Write A C++ Program To Find Denomination Needed for A Given Amount Along With The Total Number of Notes .

Generally Notes are used in banks are given below in descending Order .Ii is dependent to country wise their are some country Denomination 

INDIA ( Rupees )            USA ( Dollar )             INDIA ( Rupees ) 
( Before 8 Nov. 2016 )     ( Present )                        ( Present )
                                                               
1000                                 100                                     2000
500                                    50                                        500
100                                    20                                        100
50                                      10                                          50
20                                        5                                          20
10                                        2                                          10
5                                          1                                            5   
2                                                                                        2  
1                                                                                        1

Logic :- The Logic Behind we have to divide a money by Above Money lets take a example Suppose money is 16108 then follow the Step We are taking a example of Indian Currency In present 

Step 1:- Then First we divide 16108  by 2000 then we get 8    ,2000 rs notes then go to step 2

Step 2:-  After divide 2000 we get a remainder 108 The we know that 108 is not divisible by 500 so go to next step 

Step 3:- Now divide 108 by 100 then we get 1 ,100 rs note now remainder is 8 go to next step

Step 4:- 8 is divisible by 50 and 20 nor 10 so we escape now go to next step

Step 5:- Now divide 8 by 5 we get a 1 ,5 rs notes and remainder is 3 so go to next step

Step 6:- Now divide 3 by 2 we get 1 ,2 rs notes and remainder is 1
so follow the next step 

Step 7:- This is a Last step divide 1 by 1 we get zero remainder now print the total no of denomination needed and along with total no of count require to fulfill a requirement 

So for 16108 You Need to 

No.

8 * 2000 = 16000
1 * 100 = 100
1 * 5 = 5
1 * 2 = 2
1 * 1 = 1

Total =12 Notes For minimum Transaction

See Also :- C Program For Denomination of an Amount

Solution :- 

Method 1 :- Denomination For Indian Rupees

#include<bits/stdc++.h>
using namespace std;
int main() 
{
    /*Program By Ghanendra Yadav
    Visit http://www.programmingwithbasics.com/
    */ 
  int amt, r2000=0, r500=0, r100=0, r50=0, r20=0, r10=0, r5=0, r2=0 , r1=0 ,count=0; 

  cout<<"Enter The Amount in Rupees : \n\n" ; 
  cin>>amt ; 
 
while(amt >= 2000) 
 
  r2000 = amt / 2000 ; 
  amt = amt % 2000;
  cout<<"\nTotal Number Of 2000 Rupees Notes : "<< r2000 ;
  break ; 
  }
while(amt >= 500) 
 
  r500 = amt / 500 ; 
  amt = amt % 500;
  cout<<"\nTotal Number Of 500 Rupees Notes : "<< r500 ;
  break ; 
 
  while(amt >= 100) 
 
  r100 = amt / 100 ; 
  amt = amt % 100;
  cout<<"\nTotal Number Of 100 Rupees Notes : "<< r100 ;
  break ; 
 
  while(amt >= 50) 
 
  r50 = amt / 50 ;
  amt = amt % 50; 
  cout<<"\nTotal Number Of 50 Rupees Notes : "<< r50 ; 
break ; 
  }  
  while(amt >= 20) 
 
  r20 = amt / 20 ; 
  amt = amt % 20;
  cout<<"\nTotal Number Of 20 Rupees Notes : "<< r20 ; 
  break ; 
  }  
  while(amt >= 10) 
 
  r10 = amt / 10 ; 
  amt = amt % 10;
  cout<<"\nTotal Number Of 10 Rupees Notes Or Coin : "<< r10 ; 
  break ; 
 
  while(amt >= 5) 
 
  r5 = amt / 5 ; 
  amt = amt % 5;
  cout<<"\nTotal Number Of 5 Rupees Notes Or Coin : "<< r5 ; 
  break ; 
 
  while(amt >= 2) 
 
  r2 = amt / 2 ; 
  amt = amt % 2;
  cout<<"\nTotal Number Of 2 Rupees Notes Or Coin : "<< r2 ; 
  break ; 
 
  while(amt >= 1) 
 
  r1 = amt / 1 ; 
  amt = amt % 1;
  cout<<"\nTotal Number Of 1 Rupees Note Or Coin : "<< r1 ; 
  break ; 
  }
count = r2000 + r500 + r100 + r50 + r20 + r10 + r5 + r2 + r1;   
  cout<<"\n\nTotal Number Of Notes Require :"<< count<<endl ; 
return 0;  
}

Method 2 :- Denomination For USA Dollar

#include<bits/stdc++.h>
using namespace std;
int main() 
{
    /*Program By Ghanendra Yadav
    Visit http://www.programmingwithbasics.com/
    */ 
  int amt, r100=0, r50=0, r20=0, r10=0, r5=0, r2=0 , r1=0 ,count=0; 

  cout<<"Enter The Amount in Rupees : \n\n" ; 
  cin>>amt ; 

  while(amt >= 100) 
 
  r100 = amt / 100 ; 
  amt = amt % 100;
  cout<<"\nTotal Number Of 100 Dollar Notes : "<< r100 ;
  break ; 
 
  while(amt >= 50) 
 
  r50 = amt / 50 ;
  amt = amt % 50; 
  cout<<"\nTotal Number Of 50 Dollar Notes : "<< r50 ; 
break ; 
  }  
  while(amt >= 20) 
 
  r20 = amt / 20 ; 
  amt = amt % 20;
  cout<<"\nTotal Number Of 20 Dollar Notes : "<< r20 ; 
  break ; 
  }  
  while(amt >= 10) 
 
  r10 = amt / 10 ; 
  amt = amt % 10;
  cout<<"\nTotal Number Of 10 Dollar Or Coin : "<< r10 ; 
  break ; 
 
  while(amt >= 5) 
 
  r5 = amt / 5 ; 
  amt = amt % 5;
  cout<<"\nTotal Number Of 5 Dollar Or Coin : "<< r5 ; 
  break ; 
 
  while(amt >= 2) 
 
  r2 = amt / 2 ; 
  amt = amt % 2;
  cout<<"\nTotal Number Of 2 Dollar Or Coin : "<< r2 ; 
  break ; 
 
  while(amt >= 1) 
 
  r1 = amt / 1 ; 
  amt = amt % 1;
  cout<<"\nTotal Number Of 1 Dollar Or Coin : "<< r1 ; 
  break ; 
  }
count = r100 + r50 + r20 + r10 + r5 + r2 + r1;   
  cout<<"\n\nTotal Number Of Dollar Require :"<< count<<endl ; 
return 0;  

}

See Also :- Java Program For Denomination of an Amount

Output:-


C++ Program For Denomination of an Amount

C++ Program For Denomination For USA Dollar



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Hi, I’m Ghanendra Yadav, SEO Expert, Professional Blogger, Programmer, and UI Developer. Get a Solution of More Than 500+ Programming Problems, and Practice All Programs in C, C++, and Java Languages. Get a Competitive Website Solution also Ie. Hackerrank Solutions and Geeksforgeeks Solutions. If You Are Interested to Learn a C Programming Language and You Don't Have Experience in Any Programming, You Should Start with a C Programming Language, Read: List of Format Specifiers in C.
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