**Problem :-**Write A Program To Check Year Is Leap Year Or Not .Means Year Has 366 Days in Year .

**Logic :-**We Know that leap year have 366 Days in a year ,so if year is divide by 4 and 400 then year is leap year or one more condition if year divide by 100 then Year Is Not leap year or Leap Year Comes Every 4 Years Like

1992 ,1996 ,2000 ,2004 ,2008 ,2012 ,2016 ,2020 These are leap Years.

**Solution :-**

#include<iostream>

using namespace std;

int main()

{

//By-Ghanendra Yadva

int year;

cout<<"Enter The Year You Want To Check : \n";

cin>>year;

if((year%4)==0 && (year%400)==0)

{

cout<<"\nYear Is Leap Year\n";

}

else if(year%100==0)

cout<<"\nYear Is Not Leap Year\n";

else

cout<<"\nYear Is Leap Year\n";

return 0;

}

**Output:-**

The given program out put is wrong. The Program is

ReplyDelete{

int year;

cout<<"Enter The Year You Want To Check : \n";

cin>>year;

if((year%4)==0)

{

cout<<"\nYear Is Leap Year\n";

}

else if(year%400==0)

cout<<"\nYear Is Leap Year\n";

else

cout<<"\nYear Is Not Leap Year\n";

return 0;

}