**Problem :-**Write A Program To Check Number Is Armstrong Or Not

**Armstrong Number :-**An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 371 is an Armstrong number since 3**3 + 7**3 + 1**3 = 371 source Click Here

**Logic :-**Logic is very simple you have to you have to separate all digit and sum of the cube of digit find

**Example :-**let's check 371

then divide by 10 we got 371/10=1 .cube of 1 is 1 store this result and again divide by 10 we got 37/10=7 . cube of 7 is 343 store and add to previously got result 1 so now its become 344 ,again divide by 10 we got 3/10=3 cube of 3 is 27 ,Now again add 27+344=371

so the Number is Armstrong Number

**Note :-**Divide the number by 10 until it become Zero

**Solution :-**

**#include<iostream>**

using namespace std;

int main()

{

//By-Ghanendra Yadav

int i,n1,num=0,n2,rem;

cout<<"Enter The Number :\n";

cin>>n1;

n2=n1;

while(n1!=0)

{

rem=n1%10;

num=num+rem*rem*rem;

n1=n1/10;

}

if(num==n2)

cout<<"Number is Armstrong\n";

else

cout<<"Number is not Armstrong\n";

return 0;

}

**Output:-**

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