Hacker Rank solution For Day 19: Interfaces

Problem:- Write a Hackerrank Solution For Day 19: Interfaces or Hacker Rank Solution Program In C++ For " Day 19: Interfaces " or Hackerrank 30 days of code Java Solution:Day 19: Interfaces solution or Hackerrank solution for 30 Days of Code Challenges or Hackerrank 30 days of code Java Solution, Day 19: Interfaces solution, or C/C++ Logic & Problem Solving: Day 19: Interfaces or Hacker Rank Solution For Day 19: Interfaces.

Check This:- Hacker rank solution for Strings, Classes, STL, Inheritance in C++.

Explanation:- This is a very simple problem(Interfaces) we have to just calculate divisor sum and print the sum of the divisor. we can do this by run the loop(started with 1 and end with N) and put the condition if number N is divided by I(where I = 1 to N) than the sum of the divisor is added each time when if N%I==0. Let's take an example and try to understand the problem step by step.

Example:- Let's assume Number N is 24 and we have to calculate the Divisor sum so we divide the number by I=1 to I=24 with the help of "For Loop" Take a look at step by step.

Step 1: If(N % I ==0) then Sum or total is Sum = Sum + I Or Total = Total + I.

Step 2: Print the total outside the "For Loop". Here Divisor of 24 = 1 + 2 + 3 + 4 + 6 + 8 + 12 + 24 = 60.

Also Check:- Geeksforgeeks solution for School, Basic, Easy, Medium, Hard in C++.

Tip:- Copy the colored code or full code(According to Requirement ) and paste it into hacker rank editor.All solution provided here are in C++ (CPP) if any reader wants these solutions in C, and Java comments below or Email me with your query like " day n solution in C / C++ / Java. Check the end of the post solutions with the full explanation
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#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
#include <string>
using namespace std;
class AdvancedArithmetic
        virtual int divisorSum(int n)=0;

struct Calculator : public AdvancedArithmetic
    int divisorSum(int n)
    int total=0,i;
        for(i=1; i<=n; i++)
            if(n%i == 0)
        return total;

int main()
    int n;
    cin >> n;
    AdvancedArithmetic *myCalculator = new Calculator(); 
    int sum = myCalculator->divisorSum(n);
    cout << "I implemented: AdvancedArithmetic\n" << sum;
    return 0;


Hacker Rank solution For Day 19: Interfaces

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Ghanendra Yadav

Ghanendra Yadav

Hello, I Am Ghanendra Yadav Owner of This Blog, I am professional Blogger and Programmer. I Love Programming, Logo Making, And Banner Designing. My Highest Qualification is MCA From NIT Warangal. You Can Find Me On Social Media Through Below Link And If You Have Any Query Related To Programming And Other Subject Comment Below or You Can Mail Me I Will Try To Answer Within 24 Hours Email:- yghanendra@student.nitw.ac.in

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