3/07/2017

Geeksforgeeks Solution For " Smaller and Larger "

GeeksforGeeks Solution For School Domain .Below You Can Find The Solution Of Basic ,Easy ,Medium ,Hard .You Can Also Direct Submit Your Solution to Geeksforgeeks Same Problem .You Need to login then you can submit you answers 

Problem :- Given a sorted array and a value x, find the number of array elements less than or equal to x and elements more than or equal to x. 

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Solution :-

#include <iostream>
#include <vector>
using namespace std;
int main() 
{
int t1;
cin>>t1;
while(t1--)
{
  int n,x,i,count=0,temp=0;
  cin>>n>>x;
  vector <int> arr(n);
  
  for(i=0;i<n;i++)
   cin>>arr[i];
   
   for(i=0;i<n;i++)
   {
       if(arr[i]<=x)
       temp++;
       else if(arr[i]>=x)
       count++;
   }
   cout<<temp<<" "<<count<<endl;
}    

return 0;
}

Output:-

Geeksforgeeks Solution For " Smaller and Larger "

Ghanendra Yadav

Ghanendra Yadav

Hello, I Am Ghanendra Yadav Owner of This Blog, I am professional Blogger and Programmer. I Love Programming, Logo Making, And Banner Designing. My Highest Qualification is MCA From NIT Warangal. You Can Find Me On Social Media Through Below Link And If You Have Any Query Related To Programming And Other Subject Comment Below or You Can Mail Me I Will Try To Answer Within 24 Hours Email:- yghanendra@student.nitw.ac.in

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