Saturday, 31 October 2015

C++ Program To Check Year Is Leap Year Or Not

Problem :- Write A Program To Check Year Is Leap Year Or Not .Means Year Has 366 Days in Year .

Logic :- We Know that leap year have 366 Days in a year ,so if year is divide by 4 and 400 then year is leap year or one more condition if year divide by 100 then Year Is Not leap year or Leap Year Comes Every 4 Years Like 
1992 ,1996 ,2000 ,2004 ,2008 ,2012 ,2016 ,2020 These are leap Years. 

Solution :-

#include<iostream>
using namespace std;
int main()
{
//By-Ghanendra Yadva
int year;

cout<<"Enter The Year You Want To Check : \n";
cin>>year;
if((year%4)==0 && (year%400)==0)
{
cout<<"\nYear Is Leap Year\n";
}
else if(year%100==0)
cout<<"\nYear Is Not Leap Year\n";
else
cout<<"\nYear Is Leap Year\n";
return 0;
}

Output:-

C++ Program To Check Year Is Leap Year Or Not

No comments:
Write comments

Recommended Posts × +