3/14/2016

HackerRank solution for Variable Sized Arrays In C++

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Check- Geeksforgeeks solution for School, Basic, Easy, Medium, Hard Domain.

Solution:-

#include <iostream>
#include <cstdio>
using namespace std;

int main()
{
 //Ghanendra Yadav
int n,q;
cin>>n>>q;
int** seq=new int* [n];
for(int i=0;i<n;i++)
    {
      int a;
      cin>>a;
      int* b=new int [a];
      for(int j=0;j<a;j++)
        {
          int e;
          cin>>e;
          b[j]=e;
        }
    *(seq+i)=b;
   }

  for(int i=0;i<q;i++)
  {
  int r,s;
  cin>>r>>s;
  cout<<seq[r][s]<<endl;
  }
}

Output:-

Hacker Rank solution for Variable Sized Arrays In C++


Hacker Rank solution for Variable Sized Arrays In C++



Hacker Rank solution for Variable Sized Arrays In C++


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2 comments:

  1. what is this line doing ??

    --->*(seq+i)=b; <-----

    ReplyDelete
  2. Hello,

    --->*(seq+i)=b; <----- I think this line is use for finding the sequence of the array. I find the simple solution of this problem check this one.

    Solution

    #include

    using namespace std;

    int main()
    {
    int n,q,k,i,j,a,b,data;

    cin >> n >> q;

    vector> array(n);

    for(i=0;i> k;

    for(j=0;j> data;
    array[i].push_back(data);
    }
    }

    for(i=0;i> a >> b;
    cout << array[a][b];
    cout<< endl;
    }
    }

    ReplyDelete