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Solution:-
#include <iostream>
#include <cstdio>
using namespace std;
int main()
{
//Ghanendra Yadav
int n,q;
cin>>n>>q;
int** seq=new int* [n];
for(int i=0;i<n;i++)
{
int a;
cin>>a;
int* b=new int [a];
for(int j=0;j<a;j++)
{
int e;
cin>>e;
b[j]=e;
}
*(seq+i)=b;
}
for(int i=0;i<q;i++)
{
int r,s;
cin>>r>>s;
cout<<seq[r][s]<<endl;
}
}
Output:-
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what is this line doing ??
ReplyDelete--->*(seq+i)=b; <-----
Hello,
ReplyDelete--->*(seq+i)=b; <----- I think this line is use for finding the sequence of the array. I find the simple solution of this problem check this one.
Solution
#include
using namespace std;
int main()
{
int n,q,k,i,j,a,b,data;
cin >> n >> q;
vector> array(n);
for(i=0;i> k;
for(j=0;j> data;
array[i].push_back(data);
}
}
for(i=0;i> a >> b;
cout << array[a][b];
cout<< endl;
}
}