C++ Program To Swap Two Numbers Using Functions

Problem :- Write A C++ Program To Swap Two Numbers Call By Reference/Call By Value Using Functions .

Logic :- There are two method you can use to swap Two Number using function 

1. Call by Reference

2. Call by Value

Call by Reference :- In Call by reference we pass address of variable in function not value of variable .

Call by Value :- In Call by Value we pass value of variable in function .

Solution :-

Method 1 :- Call by Reference

#include<iostream>

using namespace std;

void swap(int *x ,int *y );

//Call By Reference

int main()

{

   //By-Ghanendra Yadav

    int a,b;

    cout<<"\nEnter Two Number You Want To Swap \n";

    cin>>a>>b;

    

    swap(&a,&b);

    

cout<<"\nAfter Swapping Numbers Are Given below\n\n";

    cout<<a<<"   "<<b<<" \n";

    

    return 0;

}

void swap(int *x,int *y)

{

int z;

z=*x;

*x=*y;

*y=z;

}

Method 2 :- Call by Value

#include<iostream>

using namespace std;

void swap(int ,int );

//Call By Value

int main()

{

   //By-Ghanendra Yadav

    int a,b;

    cout<<"\nEnter Two Number You Want To Swap \n";

    cin>>a>>b;

    cout<<"\nAfter Swapping Numbers Are Given below\n\n";

    swap(a,b);

    return 0;

}

void swap(int x,int y)

{

int z;

z=x;

x=y;

y=z;

cout<<x<<"   "<<y<<" \n";

}

Output:-

1. Call By Reference

2. Call By Value