Friday, 21 October 2016

C++ Program To Reverse An Array In O(n) Complexity

Problem :- Write A C++ Program To Reverse An Array In O(n);

ARRAY :- Array act to store related data under a single variable name with an index, also known as a subscript. It is easiest to think of an array as simply a list or ordered grouping for variables of the same type. As such, arrays often help a programmer organize collections of data efficiently and intuitively.

Solution :-

#include<iostream>
using namespace std;
int main()
{
  int *a;
  int i,j,temp;
  int n;
 
  cout<<"Enter The Size of Array \n";
  cin>>n;
 
  a=new int[n];
  int l=0,h=n-1;
 
cout<<"Enter The Elements of Array \n";
  for(i=0;i<n;i++)
  cin>>a[i];
  while(l<h)
  {
  temp=a[l];
  a[l]=a[h];
  a[h]=temp;
  l++;
  h--;
  }
 
cout<<"\nReverse Array Is\n";
  for(i=0;i<n;i++)
  {
  cout<<a[i]<<" ";
    }
   return 0;
}

Output :-

C++ Program To Reverse An Array In O(n) Complexity

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