Friday, 24 November 2017

HackerRank Solution For Day 29: Bitwise AND

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Task

Given set S = {1, 2, 3, . . . . , N}. Find two integers, A and B (where A<B), from set S such that the value of A&B is the maximum possible and also less than a given integer, K. In this case, & represents the bitwise AND operator.

Basic Operators

Here are some commonly used Java operators you should familiarize yourself with & Bitwise AND (^). This binary operation evaluates to 1 (true) if both operands are true, otherwise 0 (false). In other words:

1 & 1 = 1
1 & 0 = 0
0 & 1 = 0
0 & 0 = 0

| Bitwise Inclusive OR (V). This binary operation evaluates to 1 if either operand is true, otherwise 0 (false) if both operands are false. In other words:

1 | 1 = 1
1 | 0 = 1
0 | 1 = 1
0 | 0 = 0

^ Bitwise Exclusive OR or XOR (⊕). This binary operation evaluates to 1 (true) if and only if exactly one of the two operands is 1; if both operands are 1 or 0, it evaluates to 0 (false). In other words:

1 ^ 1 = 0
1 ^ 0 = 1
0 ^ 1 = 1
0 ^ 0 = 0

~ The unary Bitwise Complement operator flips every bit; for example, the bitwise-inverted 8-bit binary number 01111001 becomes 10000110, and the bitwise-inverted signed decimal integer 8 becomes -9.

Explanation:- As we can see above in Bitwise AND if  1 and 1 then the only condition is true. In this problem, we are taking two input from the user first one in number N and second in K. Now we have to find the all set of number S = {1, 2, 3, . . . . , N}. Let's take an example and try to understand the problem "Bitwise AND" easily. suppose N=5 and K=2 then set S={1, 2, 3, 4, 5}. then the combination is below.

1. A = 1, B = 2; A & B = 0
2. A = 1, B = 3; A & B = 1
3. A = 1, B = 4; A & B = 0
4. A = 1, B = 5; A & B = 1
5. A = 2, B = 3; A & B = 2
6. A = 2, B = 4; A & B = 0
7. A = 2, B = 5; A & B = 0
8. A = 3, B = 4; A & B = 0
9. A = 4, B = 5; A & B = 1
10. A = 4, B = 5; A & B = 4

The maximum possible value of A & B (LINE NUMBER 5) that is also < (K = 2) is 1, so we print 1 on a new line. We continue to check A & B value is maximum and A & B value is less than or equal to the K.

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Solution:- Day 29: Bitwise AND


#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>

using namespace std;

int main()
{    
int T, n, k, i, j, val;
cin>>T;
    
while(T>0)
    {    
        int maximum = 0;
        cin>>n>>k;
        
        for (i=1;i<n-1;i++) 
{
            for (j=i+1;j<=n;j++) 
{
                val=i&j;
                           
if (val>maximum&&val<k) 
                    maximum = val;                    
            }    
        }
            cout<<maximum<<endl;
        T--;
    }
return 0;
}

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Output:-


HackerRank Solution For Day 29: Bitwise AND



You May Also See


1. Day 24: More Linked Lists

2. Day 25: Running Time and Complexity

3. Day 26: Nested Logic

4. Day 27: Testing

Ghanendra Yadav

Ghanendra Yadav

Hello, I Am Ghanendra Yadav Owner of This Blog, I am professional Blogger and Programmer. I Love Programming, Logo Making, And Banner Designing. My Highest Qualification is MCA From NIT Warangal. You Can Find Me On Social Media Through Below Link And If You Have Any Query Related To Programming And Other Subject Comment Below or You Can Mail Me I Will Try To Answer Within 24 Hours Email:- yghanendra@student.nitw.ac.in

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2 comments:

  1. Sir bahut hi informative website hai Apki, aur apke dwara bataye Gaye hackerrank ke sabhi solutions work Kar rahe hai , mai asha karta hu ki aap yese hi madad kare, dhanyabad

    ReplyDelete
    Replies
    1. Hi, Vikram

      Dhanyabad Aapko Meri Post Bahut Achhi lagi. Visit Karte Rahiye Aur Like, Share, Subscribe Bhi Kar Lijiye.

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