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**Task**

Given set S = {1, 2, 3, . . . . , N}. Find two integers, A and B (where A<B), from set S such that the value of A&B is the maximum possible and also less than a given integer, K. In this case, & represents the bitwise AND operator.

**Basic Operators**

Here are some commonly used Java operators you should familiarize yourself with & Bitwise AND (^). This binary operation evaluates to 1 (true) if both operands are true, otherwise 0 (false). In other words:

**1 & 1 = 1**

**1 & 0 = 0**

**0 & 1 = 0**

**0 & 0 = 0**

**|**Bitwise Inclusive OR (V). This binary operation evaluates to 1 if either operand is true, otherwise 0 (false) if both operands are false. In other words:

**1 | 1 = 1**

**1 | 0 = 1**

**0 | 1 = 1**

**0 | 0 = 0**

**^**Bitwise Exclusive OR or XOR (⊕). This binary operation evaluates to 1 (true) if and only if exactly one of the two operands is 1; if both operands are 1 or 0, it evaluates to 0 (false). In other words:

**1 ^ 1 = 0**

**1 ^ 0 = 1**

**0 ^ 1 = 1**

**0 ^ 0 = 0**

**~**The unary Bitwise Complement operator flips every bit; for example, the bitwise-inverted 8-bit binary number 01111001 becomes 10000110, and the bitwise-inverted signed decimal integer 8 becomes -9.

**Explanation:-**As we can see above in Bitwise AND if 1 and 1 then the only condition is true. In this problem, we are taking two input from the user first one in number N and second in K. Now we have to find the all set of number S = {1, 2, 3, . . . . , N}. Let's take an example and try to understand the problem "Bitwise AND" easily. suppose N=5 and K=2 then set S={1, 2, 3, 4, 5}. then the combination is below.

**1. A = 1, B = 2; A & B = 0**

**2. A = 1, B = 3; A & B = 1**

**3. A = 1, B = 4; A & B = 0**

**4. A = 1, B = 5; A & B = 1**

**5. A = 2, B = 3; A & B = 2**

**6. A = 2, B = 4; A & B = 0**

**7. A = 2, B = 5; A & B = 0**

**8. A = 3, B = 4; A & B = 0**

**9. A = 4, B = 5; A & B = 1**

**10. A = 4, B = 5; A & B = 4**

The maximum possible value of A & B (LINE NUMBER 5) that is also < (K = 2) is 1, so we print 1 on a new line. We continue to check A & B value is maximum and A & B value is less than or equal to the K.

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### Solution:- Day 29: Bitwise AND

#include <cmath>

#include <cstdio>

#include <vector>

#include <iostream>

#include <algorithm>

using namespace std;

int main()

{

int T, n, k, i, j, val;

cin>>T;

while(T>0)

{

int maximum = 0;

cin>>n>>k;

for (i=1;i<n-1;i++)

{

for (j=i+1;j<=n;j++)

{

val=i&j;

if (val>maximum&&val<k)

maximum = val;

}

}

cout<<maximum<<endl;

T--;

}

return 0;

}

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### You May Also See

1. Day 24: More Linked Lists

2. Day 25: Running Time and Complexity

3. Day 26: Nested Logic

4. Day 27: Testing

Sir bahut hi informative website hai Apki, aur apke dwara bataye Gaye hackerrank ke sabhi solutions work Kar rahe hai , mai asha karta hu ki aap yese hi madad kare, dhanyabad

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