Thursday, 6 April 2017

Geeksforgeeks Solution For " Sum of divisors "

GeeksforGeeks Solution For Hard Domain .Below You Can Find The Solution Of  School Basic ,Easy ,Medium . Or Hackerrank Solution You Can Also Direct Submit Your Solution to Geeksforgeeks Same Problem .You Need to login then you can submit you answers 

Problem :- Given a natural number, calculate sum of all its proper divisors. A proper divisor of a natural number is the divisor that is strictly less than the number.

For example, number 20 has 5 proper divisors: 1, 2, 4, 5, 10, and the divisor summation is: 1 + 2 + 4 + 5 + 10 = 22.

Submit Your Solution :- Click Here 

Solution :- 

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        int n,i,res=0;
        cin>>n;
        for(i=1;i<=n/2;i++)
        {
            if(n%i==0)
            {
                res+=i;
            }
        }
        cout<<res<<endl;
    }
    return 0;
}

Output:-



Geeksforgeeks Solution For " Sum of divisors "

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Ghanendra Yadav

Ghanendra Yadav

Hello, I Am Ghanendra Yadav Owner of This Blog, I am professional Blogger and Programmer. I Love Programming, Logo Making, And Banner Designing. My Highest Qualification is MCA From NIT Warangal. You Can Find Me On Social Media Through Below Link And If You Have Any Query Related To Programming And Other Subject Comment Below or You Can Mail Me I Will Try To Answer Within 24 Hours Email:- yghanendra@student.nitw.ac.in

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