Monday, 6 March 2017

Geeksforgeeks Solution For " Roots of Quadratic Equation "

GeeksforGeeks Solution For School Domain .Below You Can Find The Solution Of Basic ,Easy ,Medium ,Hard .You Can Also Direct Submit Your Solution to Geeksforgeeks Same Problem .You Need to login then you can submit you answers 

Problem :- Given a quadratic equation in the form ax2 + bx + c, find floor of roots of it.  For example floor of 5.6 is 5.

Submit Your Solution :- Click Here 


Solution :-

#include <iostream>
#include <cmath>
using namespace std;
int main() 
{
    int t;
    cin>>t;
    while(t--)
    {
    double a, b, c, d, root1,root2, realPart, imaginaryPart;
    cin>>a>>b>>c;
    d = b*b-4*a*c;
    if (d > 0)
    {
        root1 = (-b+sqrt(d))/(2*a);
        root2 = (-b-sqrt(d))/(2*a);
        cout<<floor(root1)<<" "<<floor(root2)<<endl;
    }
    else if (d == 0)
    {
        root1 = root2 = -b/(2*a);
        cout<<floor(root1)<<" "<<floor(root2)<<endl;    }
    else
    {
        cout<<"Imaginary"<<endl;
    }
    
    }
return 0;
}

Output:-

Geeksforgeeks Solution For " Roots of Quadratic Equation "

No comments:
Write comments

Recommended Posts × +