Thursday, 16 March 2017

Geeksforgeeks Solution For " Convert from any base to decimal "

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Problem :- Given a number and its base, convert it to decimal. The base of number can be anything such that all digits can be represented using 0 to 9 and A to Z. Value of A is 10, value of B is 11 and so on.

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Solution :-

#include <iostream>
#include<math.h>
using namespace std;
int main() 
{
int t,i,sum,l,n;
string s;
cin>>t;
while(t--)
{
   cin>>n;
   cin>>s;
   sum=0;
   l=s.length();
   for(i=0;i<l;i++)
   {
       if(s[i]>47&&s[i]<58)
       {
           sum=sum+(s[i]-48)*pow(n,l-i-1);
       }
       if(s[i]>64&&s[i]<91)
       {
           sum=sum+(10+s[i]-65)*pow(n,l-i-1);
       }
   }
   cout<<sum<<"\n";
}
return 0;
}

Output:-

Geeksforgeeks Solution For " Convert from any base to decimal "

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