Monday, 6 March 2017

Geeksforgeeks Solution For " Check if an array is sorted "

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Problem :- Given an array, write a program that prints 1 if array is sorted in non-decreasing order, else prints 0.

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Solution :-

#include <iostream>
using namespace std;

int main() 
{
int t,arr[1000],i,j,n,k;
cin>>t;
while(t--)
{
  cin>>n;k=0;
  for(i=0;i<n;i++)
  cin>>arr[i];
  
  for(i=0;i<n-1;i++)
                if(arr[i]>arr[i+1])
                {
               k=1; break;
                }      
  if(k==0)
  cout<<"1\n";
  else
  cout<<"0\n";
}
return 0;
}

Output:-

Geeksforgeeks Solution For " Check if an array is sorted "

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