Monday, 6 February 2017

Geeksforgeeks Solution For " Reverse array in groups "

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Problem :- Given an array, reverse every sub-array formed by consecutive k elements.

Input:

The first line of input contains a single integer T denoting the number of test cases. Then T test cases follow. Each test case consist of two lines. The first line of each test case consists of an integer N, where N is the size of array.The second line of each test case contains N space separated integers denoting array elements.The third line of each test case consists of an integer K.

Output:
Corresponding to each test case, in a new line, print the modified array.

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Solution :-

#include <iostream>
using namespace std;
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        int n,i,j,x,k,l;
        cin>>n;        
        int arr[n];       
        for(i=0;i<n;i++)
        cin>>arr[i];       
        cin>>x;
i=0;
k=n%x;
            while(i<n-k)
            {
                for(j=x+i;j>i;j--)
{
cout<<arr[j-1]<<" ";
}            
i=i+x;
}
for(i=n-1;i>=n-k;i--)
cout<<arr[i]<<" ";
cout<<endl;
    }
    return 0;

}

Output:-

Geeksforgeeks Solution For " Reverse array in groups "

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