3/14/2016

HackerRank solution for Variable Sized Arrays In C++

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Check- Geeksforgeeks solution for School, Basic, Easy, Medium, Hard Domain.

Solution:-

#include <iostream>
#include <cstdio>
using namespace std;

int main()
{
 //Ghanendra Yadav
int n,q;
cin>>n>>q;
int** seq=new int* [n];
for(int i=0;i<n;i++)
    {
      int a;
      cin>>a;
      int* b=new int [a];
      for(int j=0;j<a;j++)
        {
          int e;
          cin>>e;
          b[j]=e;
        }
    *(seq+i)=b;
   }

  for(int i=0;i<q;i++)
  {
  int r,s;
  cin>>r>>s;
  cout<<seq[r][s]<<endl;
  }
}

Output:-

Hacker Rank solution for Variable Sized Arrays In C++


Hacker Rank solution for Variable Sized Arrays In C++



Hacker Rank solution for Variable Sized Arrays In C++


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Ghanendra Yadav

Ghanendra Yadav

Hello, I Am Ghanendra Yadav Owner of This Blog, I am professional Blogger and Programmer. I Love Programming, Logo Making, And Banner Designing. My Highest Qualification is MCA From NIT Warangal. You Can Find Me On Social Media Through Below Link And If You Have Any Query Related To Programming And Other Subject Comment Below or You Can Mail Me I Will Try To Answer Within 24 Hours Email:- yghanendra@student.nitw.ac.in

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2 comments:

  1. what is this line doing ??

    --->*(seq+i)=b; <-----

    ReplyDelete
  2. Hello,

    --->*(seq+i)=b; <----- I think this line is use for finding the sequence of the array. I find the simple solution of this problem check this one.

    Solution

    #include

    using namespace std;

    int main()
    {
    int n,q,k,i,j,a,b,data;

    cin >> n >> q;

    vector> array(n);

    for(i=0;i> k;

    for(j=0;j> data;
    array[i].push_back(data);
    }
    }

    for(i=0;i> a >> b;
    cout << array[a][b];
    cout<< endl;
    }
    }

    ReplyDelete