C++ Program For Check Character Is Vowel Or Not Using If Else

Problem :- Write A C++ Program For Check Character Is Vowel Or Not Using If Else Statement .

Logic :- As we know that there are 26 Character in English Language and only 5 Vowel Or 21 Constant ,We also know that our keyboard support only two types of English Character Capital Of Small So only we need to compare with only 5 Character .

5 Vowels are A E I O U and rest are Constant . So just we need to compare with Capital and Small Both .

If you got the Logic then try to solve the given Problem  

Try Yourself C Program To Check Number Is Positive Or Negative

Solution :-

#include<bits/stdc++.h>

using namespace std;

int main()

{

  //Ghanendra Yadav

    char ch;

    

cout << "Enter an Alphabet :\n";

    cin >> ch;

    

    if(ch=='a'||ch=='A'||ch=='e'||ch=='E'||ch=='i'||ch=='I'||ch=='o'||ch=='O'||ch=='u'||ch=='U')

  {

        cout << ch << " Is A Vowel .\n";

    }

    else

  {

        cout << ch << " Is Not A Vowel.\n";

    }

   

    return 0;

}

Output:-